120=l^2+2l

Solution for 120=l^2+2l equation:

Simplifying
120 = l2 + 2l

Reorder the terms:
120 = 2l + l2

Solving
120 = 2l + l2

Solving for variable 'l'.

Reorder the terms:
120 + -2l + -1l2 = 2l + -2l + l2 + -1l2

Combine like terms: 2l + -2l = 0
120 + -2l + -1l2 = 0 + l2 + -1l2
120 + -2l + -1l2 = l2 + -1l2

Combine like terms: l2 + -1l2 = 0
120 + -2l + -1l2 = 0

Factor a trinomial.
(10 + -1l)(12 + l) = 0

Subproblem 1
Set the factor '(10 + -1l)' equal to zero and attempt to solve:

Simplifying
10 + -1l = 0

Solving
10 + -1l = 0

Move all terms containing l to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + -1l = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -1l = 0 + -10
-1l = 0 + -10

Combine like terms: 0 + -10 = -10
-1l = -10

Divide each side by '-1'.
l = 10

Simplifying
l = 10
Subproblem 2
Set the factor '(12 + l)' equal to zero and attempt to solve:

Simplifying
12 + l = 0

Solving
12 + l = 0

Move all terms containing l to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + l = 0 + -12

Combine like terms: 12 + -12 = 0
0 + l = 0 + -12
l = 0 + -12

Combine like terms: 0 + -12 = -12
l = -12

Simplifying
l = -12
Solution
l = {10, -12}